4x^2-16x+16+x^2-356=0

Solution for 4x^2-16x+16+x^2-356=0 equation:

4x^2-16x+16+x^2-356=0

We add all the numbers together, and all the variables

5x^2-16x-340=0

a = 5; b = -16; c = -340;
Δ = b2-4ac
Δ = -162-4·5·(-340)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-84}{2*5}=\frac{-68}{10}
=-6+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+84}{2*5}=\frac{100}{10}
=10
$